(09-30-2013 11:34 AM)UofLgrad07 Wrote: The scenario presented above by MagicKnightmare (two teams tie at the end of the year but did not play one another during the regular season) was not covered by the old Big East rules. The reason why is because every Big East team played every other Big East team once during the regular season. As a result, it was impossible for teams to tie without having played one another during the regular season.
I assume/hope the American foresaw this as a possibility and added a tie-breaker rule in case the above scenario actually happened. My guess is that they did and that any such tie would be split based on BCS ranking (since that is the default tie-breaker for pretty much everything else).
Link to official tie-breaking procedures for the AAC:
http://theamerican.org/documents/2013/8/...edures.pdf
Two-Way Tie
1. The winner of the head to head match-up will represent The American in the Bowl Championship Series.
2. If still tied, the highest-ranked team in the final BCS standings will be the BCS representative.
Three-Way Tie
1. If one team defeated both other teams, then that team shall be the representative.
2. If still tied, and if two teams defeated the third team, the third team is eliminated. The remaining two teams
revert to the two-team tie procedure.
3. If still tied, the highest-ranked team in the final BCS standings will be the BCS representative.
Four-Way Tie
1. If one team defeated the other three teams, then that team shall be the representative
2. If still tied, and three of the four teams defeated the fourth team, the fourth team is eliminated. The
remaining three teams revert to the three-way tie procedure.
3. If still tied, and two of the four teams defeated the other two teams, the latter two teams shall be eliminated.
The two remaining teams shall revert to the two-team tie procedure.
4. If still tied, the highest-ranked team in the final BCS standings will be the BCS representative.